select rank=count(*), a1.au_lname, a1.au_fname from authors a1, authors a2 where a1.au_lname + a1.au_fname >= a2.au_lname + a2.au_fname group by a1.au_lname, a1.au_fname order by ranksource: http://support.microsoft.com/default.aspx?scid=kb;en-us;186133
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